**Self-Made Capacitor Boost Circuit Schematic (1)**
The circuit shown below is a self-made capacitor boost circuit. The integrated circuit IC1 is a timer, and its output frequency is determined by the external timing components R2 and C1. The pulse signal from pin 3 of IC1 is sent to the clock input terminal of the counter IC2. IC2 is configured as a six-stage counter, and the pulse train from IC1 is sequentially distributed to the Q0 through Q5 outputs of IC2. Transistors V1 through V5 are used to charge capacitors C3 through C7, while transistors V6 and V7 discharge the charged capacitors. Since the capacitors C3 to C7 are charged to the same voltage, the output provides a DC voltage approximately five times the original charging voltage.
The power supply for this circuit has two parts: one part supplies 9V for IC1 and IC2, which consumes very little current. The other part provides a charging voltage of 3–12V for capacitors C3 to C7, resulting in an output DC voltage of about 15–50V at the OUT terminal. Depending on the application, you can choose the appropriate input voltage to achieve the desired output.
As IC2 counts and sequentially outputs signals from Q0 to Q5, V1 through V5 are turned on in sequence, allowing capacitors C3 to C7 to be charged through diodes D1 to D5. When IC2 reaches the Q5 output, both V6 and V7 are activated, and the voltage stored in the capacitors is combined with the power supply through the collector-emitter junction of V7, resulting in a DC voltage at the output that is approximately five times the charging voltage. Each cycle of IC2 results in one full charge and discharge of the capacitors, producing a pulse at the OUT terminal. After filtering through capacitor C8, the output becomes a stable DC voltage. The higher the frequency of IC2, the smoother the output voltage. Therefore, adjusting the frequency of IC1 can improve the quality of the output voltage.
This circuit is designed to provide a five-fold voltage boost but can also be modified to produce 2–8 times the voltage by adjusting the configuration of IC2. By setting it as a 2–8 stage frequency divider, the capacitors can be charged and discharged accordingly, allowing for flexible voltage output at the OUT terminal. When the output voltage is high, the capacitors C3–C8 must have sufficient voltage ratings to prevent breakdown, especially C8.
**Component Selection**
In the circuit, transistors V1 to V5 are preferably Darlington transistors, and resistors are 1/8W carbon film resistors. The 9V power supply for IC1 and IC2 can be provided by a 9V battery or another suitable source.
**Circuit Assembly and Testing**
ICs can be installed using sockets to make replacement easier. Ensure that the polarity of all capacitors is correct before powering up. After assembly, perform a thorough inspection before testing. This circuit usually works without any adjustment once powered on. It can also be used for boosting internal power supplies.
Capacitor-based voltage doublers and boost circuits offer advantages in portable electronic devices by eliminating the need for step-up transformers, replacing them with integrated circuits and capacitors. This reduces weight and improves efficiency. The circuit consists of a pulse oscillator, a frequency divider, a transistor switching stage, a storage capacitor, and an isolation diode.
**Self-Made Capacitor Boost Circuit Schematic (2)**
A gate-based voltage doubler circuit can provide the necessary high voltage for certain electronic devices. Although the output current is limited, it serves as an economical and convenient power source for applications requiring high voltage but not large current. The circuit diagram is shown in the figure.
(a) shows a voltage doubler circuit, while (b) shows a 5x voltage boost circuit.
**Self-Made Capacitor Boost Circuit Schematic (3)**
This circuit is a ten-times boost circuit using crystal diodes and capacitors. It can be used for applications such as ozone generators or combustion aids.
**Self-Made Capacitor Boost Circuit Schematic (4)**
When the circuit is unpowered, the voltage level is 0V.
After power is applied, +5V_ALWP charges capacitors C710, C722, C715, and C719 through pin 1 of D32. At this point, the voltages across the capacitors are as shown. The actual voltage at the +15V_ALWP output is 5V.
When the Y pin of U64 starts to output a square wave of 5V:
1. The voltage across C715 is 5V on the left and 10V on the right. Current flows through D35 to charge C719 to 10V.
2. Simultaneously, the 5V Y output charges C710, which then charges C722 to 10V via D32. The +15V_ALWP output now reads 10V.
When the Y pin is at 0V:
1. The voltage across C715 drops to 0V on the left and 5V on the right. C722 (10V) charges C715 to 7.5V.
2. Similarly, C722 remains at 7.5V due to the reverse bias of D32.
After several cycles, the voltage across C715 rises to 10V. When Y returns to 5V, the right side of C715 reaches 15V. Throughout the process, C715 continues to charge C719 through D35. Finally, the +15V_ALWP output reaches 15V.
**Self-Made Capacitor Boost Circuit Schematic (5)**
This circuit uses only four components to create an infinite boost. The principle is shown in Figure 1. Connect the circuit to an AC power supply with peak voltage E as illustrated in Figure 2.
The charging and discharging processes of capacitors C1 and C2 at times t1–t4 are shown in Figures 3a–d. At time t1, the power supply charges C2 to E via D1; at t2, the power supply and C2 charge C1 to 2E; at t3, the power supply and C1 charge C2 to 3E; and at t4, the power supply and C2 charge C1 to 4E. The voltages of C1 and C2 increase incrementally by E at later times. During this process, the voltage drop across each capacitor is compensated by D2 and D1, respectively.
In practice, the boosted power can be taken from either C1 or C2. For details, refer to Figure 4. The capacitance of C1 and C2 should be selected based on the load current to meet the boosting requirements. Importantly, the load should never be disconnected during operation, as this could cause overvoltage and damage the capacitors.
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